![]() And -c will give total count for the matches instead of printing them. Where -v "non" will simply ignore both nonAB and nonCD as they both have non in them. Search for AB+CD ignoring nonAB and nonCD and count URLs : grep "AB+CD" test | grep -cve "non" )Īs a self-exercise, try your hands upon grep search on file foobar. With the -v, -invert-match option (see below),Ĭount non-matching lines. Suppress normal output instead print a count of matching linesįor each input file. Thus inverting the search.Īlso, To count number of lines that matches the search, use -c switch : -c, -count It simply means that It will search for lines having those words ( here bar ), but will exclude them in final display. Invert the sense of matching, to select non-matching lines. We get this because of -v switch for which manpage explains : -v, -invert-match Will search for lines having word foo but not bar. Will search for lines having word foobar in file test.txt and display all occurrences whereas, grep "foo" -v "bar" test.txt For the time being, here goes the answer : Using grep grep "foobar" test.txt While You will get answer here, you should have a look at man grep (can be overwhelming) and some examples. ![]() In such cases you need more complicated regular expressions or other tools (like awk). ![]() One may say grep ,AB+CD,AB+CD will do, but since "the number of columns is not fixed", I guess you'd like to tell apart these two lines: ,9,AB+CD,AB+CD,AB+CD I want to print the line where there is only 'AB+CD' Notice this request makes things complicated: If I get you right it's AB+CD AND NOT (nonAB OR nonCD) grep AB+CD | grep -v -e nonAB -e nonCD Still few of your problems are solvable with it. I'm not sure if the above is a complete system when dealing with more than two patterns. Now to get NOT (foo AND bar): grep -v -E 'foo.*bar|bar.*foo' We can try to obtain foo AND bar with a single (extended) grep:Īgain lines containing foo and bar in the same line ( foo AND bar): grep -E 'foo.*bar|bar.*foo' However NOT (foo AND bar) (logically equivalent to (NOT foo) OR (NOT bar)) is not that easy. Which is equivalent to (NOT foo) AND (NOT bar): grep -v foo | grep -v bar This makes NOT (foo OR bar) possible: grep -v -e foo -e bar The problem is -v is not restricted to a single pattern, it's global to entire grep (at least in my Debian). With these bricks you can build your logic. Lines not containing baz ( NOT baz): grep -v baz Lines containing foo and bar in the same line ( foo AND bar): grep foo | grep bar Lines containing foo plus lines containing bar ( foo OR bar): grep -e foo -e bar
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